Aset of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. find the value that is –1 standard deviation away from the mean.

One standard deviation below the mean is 36.7

One standard deviation above to mean is 53.3

Idk which one your looking for

36.7

Step-by-step explanation:

If the value is −1 standard deviation from the mean, the z-score is −1.

−1−8.336.7===x1−458.3x1−45x1

The value 36.7 is −1 standard deviation from the mean.

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3