Stuck on 39 and 40. 39 only has 1 zero

Question 40:

- 3i + 2i/ 1 + 4i

Solution your input: Simplify is 9i

Polar Form: For a complex number a + bi, polar form is given by

r(COS(0) + i SIN(0)), where r = sqrt (a)^2 + (b)^2

0 = atan (b/a

We have that a = 0 and b = 9

Thus r = sqrt (0)^2 + (9)^2 = 9

Also, 0 = atan (9/0) = pie/2

Therefore, 9i = 9 COS (pie/2) + 9i SIN (pie/2)

Inverse:

The inverse of 9i is 1/9i

Multiply and divide by i (Keep in mind that i^2 = - 1)

(i/9i) = ( - i/9)

This means that 1/9 = - i/9

Conjugate:

The conjugate of a + ib is a - ib

the conjugate of 9i is - 9i

Modulus:

The modulus of a + ib is sqrt a^2 + b^2 the modulus of 9i is 9

9i = 9i = 9.0i

The polar form of 9i is 9i

the inverse of 9i is i/9i = - i/9 ~~ - 0.11111111111111 i

The conjugate of 9i is - 9i = - 9.0i

The modulus of 9i is 9

Question 39).

(x + 2)^3 = 0

Hope this helps ( Question 40) 9i

hows it hangin lol

step-by-step explanation: