(06.01) in the below system, solve for y in the first equation. x + 3y = 6 2x − y = 10 one thirdx + 2 negative one thirdx + 6 −x + 2 negative one thirdx + 2

we have that

x + 3y = 6 > first equation

2x − y = 10

x + 3y = 6> substract x both sides

-x+x+3y=6-x

3y=6-x> divide by 3 both sides

y=(6-x) /3

y=2-(x/3)

y=-(x/3)+2

therefore

the answer is

negative one thirdx + 2

the answer is 62

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)