Find the area created by the overlapping circles given the following information. circle a: radius = 6in and m∠cad = 90° circle b: radius = 8in and m∠cbd = 60° round your answer to the nearest hundredth if necessary. 5.83 in2 10.27 in2 16.10 in2 27.68 in2

The area of a circular sector of central angle α (in radians) in a circle of radius r is given by

... A = (1/2)r²×(α - sin(α))

Your area is expected to be computed as the sum of the areas of a sector with angle π/3 in a circle of radius 8 and a sector with angle π/2 in a circle of radius 6.

... A = (1/2)8²×(π/3 - sin(π/3)) + (1/2)6²×(π/2 - sin(π/2))

... A ≈ 16.07

Radii are in inches so the units of area will be in². The appropriate choice is

... 16.10 in²

It should be noted that the geometry described is impossible. Chord CD of circle A will have length 6√2 ≈ 8.4853 inches. Chord CD of circle B will have length 8 inches. They cannot both be the same chord.

b

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i think the answer is seven, for if i'm being useless °ω°

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