Arectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4). what is the location of q? a) (-4, -3) b) (-3, -4) c) (3, 4) d) (4, 3)

The answer is the option D, which is: D)

The explanation for this exercise is shown below:

1. By definition, the rotation of a figure is a transformation where it is rotated about a point.

2. The rectangle of this problem is rotated about the origin. According the this rule, the point of the preimage has the notation () and the point of the rotated image has the notation (). Therefore if , then the location of is ()

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day