Asquirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. if the squirrel's centripetal acceleration is 0.43 m/s 2 , what is the radius of the circle? 0.60 m 1.2 m 0.36 m 0.84 m

Radius of the circle, r = 0.60 meters.

Step-by-step explanation:

It is given that,

Speed of the squirrel, v = 0.51 m/s

The centripetal acceleration of the squirrel,

We need to find the radius of the circle. The centripetal acceleration is given by :

r = 0.60 m

So, the radius of the circle is 0.60 meters. Hence, this is the required solution.

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?