The sum of two numbers is 37. five times the smaller number exceeds four times the larger number by five. find the numbers.

The sum of two numbers is 37. five times the smaller number exceeds four times the larger number by five. find the numbers.
x+y=37
5x=4y+5
x+(4y+5)/5=37
x=20 and y=17

The answer to your question is x=20 and y=17

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm