Astudent expanded an expression, as shown. is the student's work correct? explain why or why not.     −6 ( 4x − 2/ 13 ) −6(4x) + 6 ( − 2/13) −24x − 12/13

The student made an error by expressing the product of two negative signs as a negative sign instead of a positive sign to have a correct expression of  -24x + 12/12

Expressions are functions having more than one term.

Given the expression expanded by a student as   −6 ( 4x − 2/ 13 )

Expanding using the distributive theorem;

= −6 ( 4x − 2/ 13 )

= -6(4x) -6(-2/13)

= -24x + 6(2/13)

= -24x + 12/12

The student made an error by expressing the product of two negative signs as a negative sign instead of a positive sign to have a correct expression of  -24x + 12/12

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option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.