What is the surface area of the regular pyramid below? if able can you do a step by step as to how to do this (wil mark as the brainliest)

The total surface area of a regular pyramid is the sum of the areas of its lateral faces and its base.
The area of the faces = four times the area of the triangle
                                   = 4 * ( 0.5 * height * base )
                                   = 4 * ( 0.5 * 8 * 15 ) = 240
The area of the base = area of a square
                                  = 8 * 8 = 64 

So, the total area = 240 + 64 = 304 sq. units

2xy/9 is the answer to this problem