Is there enough information to conclude that the two triangles are congruent? if so, what is a correct congruence statement? question 18 options: yes;   δcab   ≅ δdac yes; δabc   ≅ δacd yes;   δacb   ≅ δacd no, the triangles cannot be proven congruent.

Yes,  Δ ACB  ≅ Δ ACD

Step-by-step explanation:

Since, Here ABD is a triangle in which AB = AD

Therefore, ABD is the isosceles triangle,

Also, AC is altitude of the  isosceles triangle ABD.

Therefore, AC will be the median of the triangle ABC ( By the property of isosceles triangle )

Thus, BC = CD

Now, In Δ ACB and Δ ACD,

AB ≅ AD (given)

CB≅CD ( Because CB= CD)

And, AC≅AC  ( Reflexive)

Therefore By SSS postulate of congruence,

Δ ACB ≅Δ ACD

Thus, Third Option is correct.

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)