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![\bf \begin{cases} f(x)=x-6\\ g(x)=x^{\frac{1}{2}}(x+3) \end{cases} \\\\\\ f(x)\cdot g(x)\implies (x-6)\cdot \left[ x^{\frac{1}{2}}(x+3) \right]\implies (x-6)\cdot \left[ \stackrel{distributing}{x^{\frac{3}{2}}+3x^{\frac{1}{2}}} \right]](/tpl/images/0093/2712/5a6de.png)
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If f(x)=x-6 and g(x)=x^1/2(x+3) what is f(x) times g(x...
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