**urgent** steve is one-fourth as old as his father. in five years, steve will be one-third as old as his father will be. find their present ages.

Let's have Steve's age be x, and his father's age be f
Then, we can set up equations
Steve is one-fourth as old as his father goes to an equation as x=(1/4)f
In five years (x+5), Steve will be one-third as old as his father will be (f+5). This goes to an equation as x+5=(1/3)(f+5)
We can then solve the first equation for either variable (I will be doing f), and plug it in for a system of equations. 

x=(1/4)f
4x=f ← plug that in for f in the next equation

x+5 = (1/3)(4x+5) ← Solve this for x
3(x+5)=4x+5
3x+15=4x+5
3x+10=4x
10=1x
x=10

Therefore, Steve's age is 10. His father's age is f=4x, plug in 10 for x, and his father's age is 40

62926281916 inches of rain: )

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )