Gfind the equation of the line (in slope intercept form) passing through the point (4,3) and parallel to the line passing through (1,2) and (4,2).

The points (1, 2) and (4, 2) both have the same y-value, so that is the horizontal line y = 2.

The given point has y-value of 3, so the line passing through it will be

... y = 3

There is no x-term because the slope is 0. We could write it as

... y = 0x +3

but this simplifies to

... y = 3

answer: what equations are there

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this