Charlene puts together two isosceles triangles so that they share a base, creating a kite. the legs of the triangles are 10 inches and 17 inches, respectively. if the length of the base for both triangles is 16 inches long, what is the length of the kite’s other diagonal?

We have to solve for the long diagonal.

Upper half of long diagonal^2 = 10^2 -8^2
Upper half of long diagonal^2 =100 -64
Upper half of long diagonal^2 =36

Upper half of long diagonal = 6

Lower Half of long diagonal^2 = 17^2 -8^2
Lower Half of long diagonal^2 = 289 -64
Lower Half of long diagonal^2 = 225

Lower Half of long diagonal = 15

Long Diagonal = 6 + 15 = 21 inches

You can use a calculater and divide the minutes by the $$, hope that you

The 3rd quadrant as 3x+g5ti=56i: 92d-543