Mathematics
Mathematics, 15.07.2019 20:00, jholland03

Prove parallelogram side theorem for segments

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Mathematics, 25.06.2019 06:20, antcobra
Uproving the parallelogram diagonal theorem angles segments triangles statements reasons given: abcd is a parallelogram. diagonals ac, bd intersect at e. prove: ae = ce and be de def of parallelogram parallelogram side theorem def of alt interior angles alternate interior angles theorem statements 1 abcd is a parallelogram reasons 1. given
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Mathematics, 14.07.2019 08:00, romanbattistelli23
Given: abcd is a parallelogram. prove: any two consecutive angles of abcd are supplementary. the quadrilateral abcd is a parallelogram, so by definition ab¯∥cd¯. it follows that ad¯ is a transversal of parallel line segments ab¯ and cd¯, which makes ∠a and ∠d same-side interior angles along parallel line segments. likewise, bc¯ is a transversal of parallel line segments ab¯ and cd¯, so ∠b and ∠ are same-side interior angles along parallel line segments therefore, applying the same-side interior angles theorem, it is possible to conclude that ∠a is to ∠d and ∠b is to ∠ using the same line of reasoning, but instead consider that ad¯ is parallel to segment and these parallel lines are cut by transversals cd¯ and ab¯. therefore, it is possible to conclude that ∠a is to ∠b and ∠c is supplementary to ∠d. enter the words or names that correctly fill in the blanks to complete the proof. make sure your answers are in order and separate them with commas, like this: x, opposite, xy c, a same-side interior angle , bc
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Mathematics, 12.10.2019 19:30, colyernicholas44
Proving the parallelogram side theorem given: abcd is a parallelogram, prove: ab cd and bc da angles segments triangles su nes zbac 2bca dac zdca statements reasons assemble the proof by dragging tiles to the statements and reasons colus.
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