If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . if 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is

There is some inforrmation that is missing in this question. It should read:

A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .

Answers
Part 1.   0.02
Part 2.  0.0375

Explanation
The probability is a chance of an event happening. It is calculated as;
probability = (Number of favourable outcome)/(Number of available outcome)

Part 1
6 are chosen at random. If 4 are not defective, then 2 are defective.
P(at least 4 are not defective) = 4/40 × 2/10
                                                = 1/10 ×1/5
                                                = 1/50
                                                 = 0.02

Part 2
8 are chosen at random. If 3 are defective, the 5 are not defective. 
P(3 are defective) = 3/40 × 5/10 
                             = 15/400
                             = 3/80
                            = 0.0375