The image of a parabolic lens is projected onto a graph. the image crosses the x-axis at –2 and 3. the point (–1, 2) is also on the parabola. which equation can be used to model the image of the lens? y = -1/5 (x – 2)(x + 3) y = -1/3(x – 2)(x + 3) y = -1/2 (x + 2)(x – 3) y = 1/4 (x + 2)(x – 3)

For x-intercepts "b" and "c", a quadratic can be written as
  y = a(x -b)(x -c)

You know the x-intercepts, so you can write the equation as
  y = a(x +2)(x -3) . . . . . . eliminates the first two answer choices

Substituting (x, y) = (-1, 2), you have
  2 = a(-1+2)(-1-3) = -4a
Then dividing by -4 gives
  -2/4 = a = -1/2 . . . . . corresponds to the third answer choice

The appropriate selection is
  y = -1/2 (x + 2)(x - 3)

Cis your correct answer

The linear equation is: y=ax+b