Mathematics, 16.07.2019 05:00, SissyBoo9680
1). what is an equation of the line that is perpendicular to y=−4/5x+3 and passes through the point (4, 12) ? 2). what is an equation of the line that is perpendicular to −x+3y=9 and passes through the point (−3, 2) ?
Answers: 1
and 12 = 5 + b. b = 7. So the equation you need is 
. For 2.) we need to find the slope of the line since it's not apparent the way it is written. Solve it for y to find the slope. 3y=x+9 and 
. The slope is 1/3 so the opposite reciprocal is -3. That's the perpendicular slope. Using point (-3, 2) where x = -3 and y = 2, we will write the equation and solve for b. 
and 2 = 9+b so b = -7. Our new equation then is y=-3x-7. There you go!
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