Mathematics, 16.07.2019 06:30, yaaaaa31gghgf
Solve the equation on the interval [0, 2π). tan^2x sin x = tan^2x
Answers: 1
. Factor out the common tan^2x like this: 
. Now we have 2 separate equations to solve: 
and sinx = 0. Now we have to figure out where tan^2 is 0 between 0 and 2pi. If we include 2pi, the solutions for that equation are 
. You can test those out on your calculator just to be sure. There's only one value of x for the next equation. The only place between 0 and 2pi where the sin x = 1 is at x = 
. And there you go!
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Solve the equation on the interval [0, 2π). tan^2x sin x = tan^2x...
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