The population of a midwestern city decays exponentially. if the population decreased from 900,000 to 800,000 from 2003 to 2005, what will be the population in 2008?

Hello.   


Let 2003 be the zero year; then 2005 is the three year, and 2008 the 5 year.

P = ab^x
---
P(3) = ab^3 = 800000
P(0) = ab^0 = 900000

---
a = 900000
Solve for "b"::
b^3 = 8/9 
b = 2/cbrt(9) 

Equation::
P(x) = 900000^x

Ans: P(5) = 900000

Have a nice day

The graph isn’t that clear