Can you use the asa postulate or the aas theorem to prove the triangles congruent? by aas only neither apply by asa only both apply

(C) by ASA only

Step-by-step explanation:

Let us name the given figure, there are two triangles that areΔABO and ΔCOD.

Thus, from ΔABO and ΔCOD, we have

∠ABO=∠DCO(Given in the question)

BO=DO( given in question)

∠AOB=∠COD(Vertically opposite angles)

Therefore, by ASA rule,

ΔABO ≅ΔCOD

Therefore, only ASA rule can be applied on the given figure.

Hence, option C is correct.

1/2*qr*rs

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4