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Mathematics, 16.07.2019 11:00, jahmanilittlejotz1pe
Solve a(x − b) − 2k = l for k. a. k = −fraction one half [l − a(x − b)] b. k = fraction one half [l − a(x − b)] c. k = −2l − ax − ab d. k = −2l + ax − ab
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Solve a(x − b) − 2k = l for k. a. k = −fraction one half [l − a(x − b)] b. k = fraction one half [...
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