Aprofessor is examining a new strain of bacteria. the amount of bacteria can be modeled by function s(n) = 20 · bn, where n is the number of hours and b is an unknown positive base. based on the model, there were initially bacteria. if b = 1.85, the hourly percent growth rate of the bacteria would be

For this case we have a function of the form:
 
 Where,
 A: initial amount
 b: growth rate (if b> 1)
 n: time in hours
 Substituting values we have:
 
 We have then that the initial amount is:
 
 If b = 1.85 then the growth percentage is:
 
 
 here were initially 20 bacteria.
 The hourly percent growth rate of the bacteria would be 85%

Hope this ; )