Acompany offered one half of its employees a bonus if the production of light bulbs increased by 20%. the other half of the employees was not offered a bonus. as the end of the month, production in the group that did not get the bonus offer increased by a mean of 15 and production in the bonus group increased by a mean of 10. what is the correct order of steps to determine if the results are significant? a. randomly separate the employees' individual results into two groups. b. calculate the mean of each group. c. calculate the difference of the means. d. run the experiment many times. e. calculate the probability of a difference of 5. select one: a. a, b, c, d, e b. d, e, a, b, c c. c, e, a, b, d d. a, b, d, c, e

14. (05.02 lc) what is the value of y in the solution to the following system of equations? (5 points) 2x + y = −4 5x + 3y = −6

The areas of two similar triangles are 72dm2 and 50dm2. the sum of their perimeters is 226dm. what is the perimeter of each of these triangles?

Asystem of linear equations with more equations than unknowns is sometimes called an overdetermined system. can such a system be consistent? illustrate your answer with a specific system of three equations in two unknowns. choose the correct answer below. a. yes, overdetermined systems can be consistent. for example, the system of equations below is consistent because it has the solution nothing. (type an ordered pair.) x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 6 b. no, overdetermined systems cannot be consistent because there are fewer free variables than equations. for example, the system of equations below has no solution. x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 12 c. yes, overdetermined systems can be consistent. for example, the system of equations below is consistent because it has the solution nothing. (type an ordered pair.) x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 8 d. no, overdetermined systems cannot be consistent because there are no free variables. for example, the system of equations below has no solution. x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 24