What is the equation of a line, in general form that passes through point (1,-2) and had a slope of 1/3 3x-y-7=0 x-3y+7=0 x-3y-7=0

Step-by-step explanation:

The equation of line passing from point (a,b) and has slope m is given by :-

Given : Point = (1,-2)

Slope of line=

Now, the equation of a line that passes through point (1,-2) and had a slope of will be :-

Hence, the  equation of a line, in general form that passes through point (1,-2) and had a slope of is

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it