If neil, weighing 150 pounds, jumps with an initial velocity of 8ft/sec, calculate his hang time on the earth as well as his hang time on the moon, given that the moon has one-sixth the gravitational pull of the earth. then calculate the maximum height of his jump in each location..

we use the following formula to calculate height, 'h', under the effect of gravity: 

h = vt - (1/2)gt^2, where g = 9.8m/s^2 and 't' represents time in seconds

8 ft/s * 0.3048 = 2.4384 m/s

we treat mass as inconsequential to the problem, considering only the effect of initial velocity and gravitational pull

to find his 'hang time' we solve for h=0, knowing that t=0 will be the first value (before the jump): 

0 = 8(0.3048)t - (9.8/2)t^2

solving for 't' we have t=0.497

the 'hang time' will be approximately 0.5 seconds, or 1/2 of a second

the maximum height will be 0.2488m, or 0.816 feet, or 9.8 inches

on the moon, the hang time and height will increase by a factor of 6

hang time: approximately 3 seconds on the moon

maximum height: approximately 2.4 feet

where are the choices?

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .