Describe how the graph of y= x2 can be transformed to the graph of the given equation. y = (x-10)2+8 shift the graph of y = x2 left 10 units and then down 8 units. shift the graph of y = x2 up 10 units and then right 8 units. shift the graph of y = x2 left 10 units and then up 8 units. shift the graph of y = x2 right 10 units and then up 8 units.

We have 
y= x²> y = (x-10)²+8

we know that
f(x)+d> a point (x,y) in f(x) becomes a> (x,y+d)> shift up by d
and
f(x-e) > a point (x,y) in f(x) becomes a> (x+e,y)> shift right by e
 in this problem
d=8
e=10
therefore

Shift the graph of y = x²
up by 8 and right by 10
the rule is
(x,y)> (x+10,y+8)
let's check it
the vertex in y= x²> (0,0)
the vertex in y = (x-10)²+8> (10,8)
so
(0,0)> (x+10,y+8)> (0+10,0+8)> (10,8)> is ok

the answer is
Shift the graph of y = x2 right 10 units and then up 8 units.

Ab=dc ac=de ad=bce i hope this !