Which equation correctly uses the law of cosines to solve for y? 92 = y2 + 192 – 2(y)(19)cos(41°) y2 = 92 + 192 – 2(y)(19)cos(41°) 92 = y2 + 192 – 2(9)(19)cos(41°) y2 = 92 + 192 – 2(9)(19)cos(41°)

Fourth option: y^2=9^2+19^2-2(9)(19) cos(41°)

The law of cosines to solve for one side is:
c^2=a^2+b^2-2ab cos C
We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)

In this case c=y, a=9, b=19, and C=41°, then:
y^2=9^2+19^2-2(9)(19) cos (41°)

This is too long-standing now get out