Evaluate 5c+cd5c+cd5, c, plus, c, d when c=\dfrac15c= 5 1 c, equals, start fraction, 1, divided by, 5, end fraction and d=15d=15d, equals, 15.

The value of 5c + cd if c = 1/5 and d = 15 is 4

Equations are expressions separated by an "equal to" sign

Given the equation 5c + cd. We are to evaluate it if c = 1/5 and d = 15

Substitute the value of c and d into the given expression:

f(c, d) = 5c + cd

f(1/5, 15) = 5(1/5) + 1/5(15)

f(1/5, 15) = 1 + 15/5

f(1/5, 15)  = 1+ 3

f(1/5, 15)  = 4

Hence the value of 5c + cd if c = 1/5 and d = 15 is 4

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1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

where is the image?

step-by-step explanation: