The length of a rectangle is two feet greater than twice its width. if the perimeter is 25 feet, find the width.”

Hello!

To solve this problem, we will use substitution and a system of equations where L=length and w=width.

L=2+2w
2L+2w=25

We know that L equals 2+2w. Lets plug that into the bottom equation and find w.

2(2+2w)+2w=25
4+4w+2w=25
4+6w=25
6w=21
w=3.5

Now that we know w, we can find L. 

L=2+7
L=9

We have found the width, but lets check our answer with the system of equations.

9=2+7
18+7=25

The width is 3.5 feet.

Hope this helps!

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!

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