Suppose we have two urns, urn 1 and urn 2. urn 1 contains 11 red marbles and 5 white marbles. urn 2 contains 7 red marbles and 13 white marbles. the experiment consists of first choosing an urn with equally likely probability, and then drawing a marble from that urn. what is the probability of choosing urn 1 and a white marble?

answer: i oofed

step-by-step explanation:

oofed=wow

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.