Write an equation for a line that is parallel to the graph of 649-01-03-00-00_files/i0220000.jpg and passes through the point at 649-01-03-00-00_files/i0220001.jpg

The graph as well as the point are not displayed. Therefore, I can only help with the concept.

The general form of the linear line is:
y = mx + c
where:
m is the slope
c is the y-intercept

1- getting the slope:
We will start by getting the slope of the graph we have using any two points on it.
The slope will be calculated as follows:
m = 

We know that the line we are looking for is parallel to the graph. This means that:
slope of the line we are looking for = slope of graph we have calculated

2- getting the y-intercept:
The equation now is:
y = mx + c
where we have calculated m in the previous step
To get the value of c, all we have to do is substitute with the given point ion the equation and solve for c

Hope this helps :)

Socrat use det app ok