If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? simplify the answer. a)2stb)2/st(not correct)c)2s/td)t/2s

To solve this problem you must apply the proccedure shown below.
 1. You have that the area of a rectangle is 16s^2t and the length is 8st^2, the widht is:
 Area=Length x Width
 Width=Area/Length
 Width=(16s^2)t/8st^2
 2. By simplifying and by applying the exponents properties, you obtain:
 Width=2s/t
 The answer is: C) 2s/t