What’s the vertex of the quadratic function f(x)=(x-8)(x-2)

The zeros are at x=8 and x=2. The x-coordinate of the vertex is halfway between, at
  x = (8+2)/2 = 5
The y-coordinate of the vertex is f(5) = (5-8)(5-2) = -9

The vertex of f(x) is (5, -9).

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