What are the ratios for sin a and cos a? sin a=20/29?

The complete question in the attached figure

we know that
in the right triangle ABC
Part a)
sin A=opposite side angle A/hypotenuse
opposite side angle A=BC-----> 21
hypotenuse=AB-----> 29
so
sin A=21/29

the answer part a) is
sin A=21/29

part b)
cos A=adjacent side angle A/hypotenuse
adjacent side angle A=AC-----> 20
hypotenuse=AB-----> 29
so
cos A=20/29

the answer part b) is
cos A=20/29

the answer is the option C)
sin A=21/29 and cos A=20/29

What’s your question.