You roll a (fair) die numbered from 1 to 6. what is the probability that the number observed is not a 1?

Since we have 6 different possibilities each number has a 1/6 possibility to be rolled.
That means the number 1 has 1/6 of probability, to find the probability to roll any but that number we subtract 1/6 from 6/6:
6/6-1/6= 5/6

ANSWER:
5/6

Idon’t understand what you’re asking..