Carol conducted a survey of four school cafeterias to find the number of students who like tacos for lunch. the results of her survey are recorded in the table below: school cafeteria surveyschool total number of students in the cafeteria number of students who like tacos a 45 12 b 40 15 c 27 9 d 32 13 which school has the greatest percentage of students who like tacos for lunch? school a school b school c school d

D = 41%

Step-by-step explanation:

To calculate what percentage of the number 32 is 13, we must create a proportion from which we can easily determine the value we are looking for.

First we create two simple equations with data that we know. We know from homework that 32 equals 100%, so we can save as 32 = 100%

The value we are looking for can be called x.

We know that x% is equal to 13 of the output value, so we can write it as x% = 13.

So we have two simple equations:

1) 100% = 32

2) x% = 13

When we compare these two equations, we get:

(100%) / (x%) = 32/13

Now we just have to solve the simple equation.

We calculate that percentage of 32 is 13

(100%) / (x%) = 32/13

(100 / x) * x = (32/13) * x

100 = 2.4615384615385 * x

100 / 2.4615384615385 = x

40.625 = x

x = 40.625

Solution:

13 equals 40.625 percent of 32

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.