Can u me on number 5,6,and 7 i will u on what u need just send me a message

5. Input 5 where the x's, 3 = 2(5) - 7 is a true statement. 10 - 7 = 3
3 < 10 - 9 is a false statement, 3 > 1 is a true statement
2 is less than or equal to 11, is a false statement (2 is less than 11, but not equal to)
18 = 30 -12 is a true statement  30 - 12 = 18, 18=18
3= 2 + 5 is a false statement, 3 is not equal to 7

6. 7 is less than or equal to 5(4) -16, 20 - 16 = 4, 7 is not less than or equal to 4. Therefore, 4 is not a solution.

7. 9(5) - 3 < 60, 45-3 < 60, 42 < 60, 42 is less than 60, so the equation is true. 
9(6) - 3 < 60, 54 - 3 <  60, 51 < 60, 51 is less than 60, so the equation is true.
6(7) - 3 < 60, 63 -3 < 60,  60 < 60, 60 is equal to 60, the equation is false.

Q5a) 3 = 2x -7

10 = 2x
x = 5. True

b) 3 < 2x -9

12 < 2x
6 < x False

c) 2 <_ x + 6

-4 <_ x True (because -4, -3, -2 ... Infinity can be values of x)

d) 18 = 6x - 12

30 = 6x
x = 5. True

e) 3 = 2 + x

x = 1. False

Q6)

7 < 5x - 16
23 < 5x
4.6 < x

4 is not a solution of this inequality (i couldnt put equal sign under the inequality but lets assume we did and 4 is still not a solution)

Q7)

9x < 63
x < 7

They dont because x is less than 7 not less than equal to 7 so this inequality is not true for this particular set

Number nine is f(x)= 40x : ) hoped i ya