If mc020-1.jpg and mc020-2.jpg, what is the domain of mc020-3.jpg?

we have

f(x)=x+7

g(x)=\frac{1}{x-13}

(fog)(x)=[\frac{1}{x-13}]+7

we know that

the denominator cannot be zero, therefore the value of x cannot be 13

The domain are all real numbers except the number 13

therefore

the answer is the option

{x|≠13}

a

Step-by-step explanation:

idk the answer but just put a

step-by-step explanation:

congruent segments

step-by-step explanation: