What is the interquartile range of this data set? 1, 5, 27, 29, 34, 37, 48, 61, 72, 84, 96 a. 45 b. 37 c. 10 d. 64

Choice A) 45



The given set of values is 
A = {1, 5, 27, 29, 34, 37, 48, 61, 72, 84, 96}
The median of this set is 37. Five values are below it; five values are above it. It is the middle most value.

Let
L = {1, 5, 27, 29, 34}
be the lower set of values smaller than the median. We see that the median of set L is 27. So Q1 = 27

Let
U = {48, 61, 72, 84, 96}
which is composed of all the values above the median
The median of the upper set of values is 72. So Q3 = 72

Subtract the first and third quartile values to get the interquartile range (IQR)
IQR = Q3 - Q1
IQR = 72 - 27
IQR = 45

Its equal to d=7.07in