In which direction does the left side of the graph of this function point f(x)=-x^4-x^3+4x-2?

Answer with explanation:

The given function is :

 

it will not pass through origin,as, f(0)=-2

It is a fourth degree polynomial.

The given function has two real roots and two imaginary roots.

Left side of the function,after drawing a line of symmetry

→lies in third Quadrant and little bit of region lies in fourth Quadrant.

→ x=0.14 (approx) ,is line of symmetry.

→In South west Direction,left side of the graph of this function point  

First locate the turning point (vertex) of the graph. which is at the coordinates x=5 and y=9 or (5; 9).to determine whether it's a maximum or mininum value, you have to discern whether the vertex's y-value is the highest value or lowest value the graph can reach. since the vertex's y-value, 9 is the highest value the graph can reach, it will be a maximum.another basic way to determine whether the vertex's value is max or min is to see if the graph is smiling or sad. if it's smiling, the turning point/vertex would be a minimum, while a sad parabola would have a maximum y-value at the vertex.