Arectangular room is three times as long as it is wide, and its perimeter is 80 meters. find the length of the room

Let the width of the room be = x

Length of the room = 3x,  Since it is three times as wide

Perimeter = 80m

Perimeter = 2*(L + W) =  2*(3x + x)  = 80

2*(3x + x)  = 80

2*(4x)  = 80

8x  = 80     Divide both sides by 8

x = 80/8

x = 10,    But length = 3x,  = 3*10 = 30

Length = 30m

The point (5, 10) will work for the rule y=x+5.y= 10 x= 510=5+510=10therefore the ordered pair (5, 10) works for the rule