Alarge coffee urn dispenses coffee at a hospital cafeteria. the cafeteria is open from 6 am until 7 pm daily. the rate at which coffee is added to the urn is modeled by the function e(x)=3x3+20e(x)=3x3+20 , where the rate is measured in cups of coffee per hour since the cafeteria opened. the rate at which coffee is dispensed from the urn is modeled by the function l(x)=5x2+10l(x)=5x2+10 , where the rate is measured in cups of coffee per hour since the cafeteria opened. what does (e−l)(4) mean in this situation? a. there are 302 cups of coffee in the urn 4 hours after the cafeteria opened. b. the rate at which the number of cups of coffee in the urn is changing 4 hours after the cafeteria opened is 302 cups per hour. c. there are 122 cups of coffee in the urn 4 hours after the cafeteria opened. d. the rate at which the number of cups of coffee in the urn is changing 4 hours after the cafeteria opened is 122 cups per hour.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

sure i'm up for it

step-by-step explanation: