Jeremy's score was 1.75 standard deviations above the mean. which kf thr following is closest to his percentile rank

The answer is 96%.

Explanation:
It is generally presumed that the scores are normally distributed.

1) You are given how many standard deviations from the mean Jeremy's score is. This is exactly the definition of the z-score. Therefore z = 1.75

2) Look at a left-tail z-table in order to find the area of the normal curve on the left of your z-score (see picture attached). A = 0.9599

3) Multiply the area by 100 in order to find the percentile:
0.9599 × 100 = 95.99
Therefore, 95.99% of the students scored less than Jeremy.

Hence, the answer is 96%.