30 points! which statement about bq←→ is correct? contact your teacher immediately if you do not see the image. question options: bq←→ is not a tangent line because ∠baq is an acute angle. bq←→ is not a tangent line because ∠bqa is an acute angle. bq ←→−is a tangent line because △abq is not a right triangle. bq←→ is a tangent line because m∠abq = 90° .

Option (4) is correct about BQ

Step-by-step explanation:

Given : From the figure : ∠BQA = 54° and ∠BAQ = 36°

Now, Since ∠BAQ = 36° > 30°  

So, ∠BAQ is not acute.

⇒ (1) is rejected.

Also, ∠BQA = 54° > 30°  

So, ∠BQA is not acute.

⇒ (2) is rejected.

Now, in ΔABQ, By using angle sum property of a triangle

∠BAQ + ∠BQA + ∠ABQ = 180°

⇒ 36° + 54° + ∠ABQ = 180°

⇒ ∠ABQ = 90°

Since, ∠ABQ is right angle so, (3) is rejected.

Now, ∠ABQ = 90° and the line which is exterior to the circle and makes right angle with the radius of the circle is always tangent to the circle.

Hence, Option (4) is correct about BQ.

Therefore, BQ is a tangent line because m∠ABQ = 90°

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

answer: check all that apply, where the options?

step-by-step explanation: