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![\left[\begin{array}{ccc}A^2+B^2=C^2\\12^2+16^2=C^2\\144+256=400\\Now,\;we\;need\;to\;find\;the\;square\;root\;of\;400.\\\sqrt{400}= 40\\If\;it\;were\;to\;be\;a\;decimal\;such\;as\;40.162\;we\;would\;round\;to\\the\;nearest\;tenths\;and\;get\;40.2\end{array}\right]](/tpl/images/0106/2478/5136d.png)
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