Aball is thrown upward from the top of a building. the function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds: f(t) = −16t2 + 48t + 100the average rate of change of f(t) from t = 3 seconds to t = 5 seconds is per second.

For this case we have the following function:
 f (t) = -16t2 + 48t + 100
 The average rate of change is:
 (f (t2) - f (t1)) / (t2 - t1)
 We have then:
 For t1 = 3:
 f (3) = -16 * (3) ^ 2 + 48 * (3) + 100
 f (3) = 100
 For t2 = 5:
 f (5) = -16 * (5) ^ 2 + 48 * (5) + 100
 f (5) = -60
 Substituting values:
 AVR = (-60 - 100) / (5 - 3)
 AVR = -80
 
 The average rate of change of f (t) from t = 3 seconds to t = 5 seconds is -80 feet per second.

29933333.33

step-by-step explanation:

6×10=604000000÷60=66666.6666766666.6667×449=29933333.33