Which equation can you use to solve for x? a. 180-x=111b. x+87=180c. x+111=180d. x+87=111

Step-by-step explanation:

Refer the attached figure

Vertical angles : Each of the pairs of opposite angles made by two intersecting lines is called vertical angles.

AB and CD are two intersecting lines at point O.

So, By definition ∠AOC and ∠DOB are the pair of vertical angles .

So,  ∠AOC = ∠DOB (vertically opposite angles are equal)  -1

We are given  ∠AOC  = 111° and  ∠DOB  = 87°+x°

Substitute the values in 1

So, an equation can you use to solve for x is

So, Option B is correct.

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.