What are the zeros of the function? f (x) = x^3 - x^2 - 6x a) -1, 0, and 3 b) -3, 0, and 1 c) -3, 0, and 2 d) -2, 0, and 3

Try this explanation:
if to re-write the function f(x)=x(x²-x-6), then to make up the equation x(x²-x-6)=0, it is possible to find the zeros requred:
x(x-3)(x+2)=0, x=0;x=-2;x=3.

D -2;0;3