Find the y-intercept for the parabola defined by this equation: y=x^2+8x+12.separate the values with a comma.

Y=x2−8x+12y=x2-8x+12to find the  x-intercept, substitute in  00  for  yy  and solve for  xx.(0)=x2−8x+12(0)=x2-8x+12rewrite the  equation  as  x2−8x+12=0x2-8x+12=0.x2−8x+12=0x2-8x+12=0since  1212  does not contain the  variable  to solve for, move it to the right side of the  equation  by subtracting  1212  from both sides.x2−8x=−12x2-8x=-12move  1212  to the left side of the  equation  by adding it to both sides.x2−8x+12=0x2-8x+12=0factor  x2−8x+12x2-8x+12  using the ac method.tap for more −6)(x−2)=0(x-6)(x-2)=0set  x−6x-6  equal to  00  and solve for  xx.tap for more =6x=6set  x−2x-2  equal to  00  and solve for  xx.tap for more =2x=2the  solution  is the result of  x−6=0x-6=0  and  x−2=0x-2=0.x=6,2x=6,2to find the  y-intercept, substitute in  00  for  xx  and solve for  yy.y=(0)2−8⋅0+12y=(0)2-8⋅0+12solve the  equation.tap for more =12y=12these are the  xx  and  yy  intercepts  of the  equation  y=x2−8x+12y=x2-8x+12.x-intercept:   (6,,0)(6,,0)y-intercept:   (0,12hope this .

Ya i could just need to know what type of math